How is Entropy Change Calculated for a Composite System?

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Homework Statement


A composite system consists of an insulated partitioned volume, shown in Figure 4.9. Side 1 contains 2 mol of a monatomic ideal gas and Side 2 contains 4 moles of the same monatomic ideal gas. Initially, the two sides are separated by a fully insulated partition (adiabatic wall) and the temperatures are 500K and 200K on sides 1 and 2 respectively. At a particular time replacing the partition by a conducting frictionless piston. Initially V1=10L and V2=5L . Let T12 be the common temperature at which equilibrium is reached and P12 the common pressure.

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a.) Find T12 (Found to be 300K)
b.) Find P12, and the new values for V1 and V2. (Found them to be 998kPa, 5L and 10L respectively)
c.) Determine ΔS, as in ΔS=ΔS1+ΔS2 (The answer is 19J/K, but I cannot seem to reach that answer)

Homework Equations


ΔS=Ncv ln(T/To) + NR ln (V/Vo)

The Attempt at a Solution


So I found ΔS1= -17.896 using T=300, To=500, V=5, Vo=10 And ΔS2= 43.278 with T=300, To=200, V=10, Vo=5. I used cv=3/2R (though I thought it should be 3/2NR, but in class we had that it should be 3/2R for this question). So these values give a ΔS of 25.382J/K, which is quite a bit off from the answer. Any help would be greatly appreciated.
 
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Everything looks good except your value for ΔS1. Check your calculation of that.
 
Ah yes that was it! Thank you!
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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