How Is Force Calculated on a Charge at the Center of a Charged Semicircle?

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The discussion revolves around a homework problem involving a semicircle of positive charge with a specific charge distribution and the calculation of the force on a point charge located at the center of curvature. The charge per unit length is defined as [lamb] = [lamb]naught cos [the], with a total charge of 12.0 microcoulombs on the semicircle and a radius of 60.0 cm. The user has calculated the force on a 3.00 microcoulombs charge at the center as -0.526N, while the textbook answer is -0.707N. There is a suggestion to post the question in the homework help section for better assistance, indicating that the user may benefit from more focused help on the problem.
mateoguapo327
help! I need help with this homework problem.

--A line of positive charge is formed into a semicircle of radius R=60.0 cm. The charge per unit length along the semicircle is described by the expression [lamb]= [lamb]naught cos [the] . The total charge on the semicircle is 12.0 microcoulombs. Calculate the total force on a charge 3.00 microcoulombs at the center of curvature.--

The figure shows the semicircle with is center at the origin going from 0 to pi. [the] is the angle formed by dragging R clockwise from the positive y axis.

the answer in the book is -0.707Nj and I got -0.526N. Can someone please help me figure out how to properly go about solving this problem?
 
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but shouldn't this go in the homework help section? you might get a better response there.
 
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