How is fxy = 1 found for finding local extreme values?

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The discussion centers on the calculation of mixed partial derivatives, specifically how to find the value of fxy = 1. Participants clarify that fxx is derived by differentiating the function f twice with respect to x, rather than using simultaneous equations. The correct approach to find fxy involves differentiating the first derivative fx with respect to y. This distinction is crucial for understanding the notation and methodology in multivariable calculus.

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Homework Statement



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The Attempt at a Solution



I don't understand how they found fxy = 1

I understand how they found fxx, they used simultaneous equations, but I don't understand that notation.
 

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bobsmith76 said:

Homework Statement



see attachment

The Attempt at a Solution



I don't understand how they found fxy = 1

I understand how they found fxx, they used simultaneous equations, but I don't understand that notation.

They didn't find ##f_{xx}## by using simultaneous equations. They just differentiated ##f## twice with respect to ##x##. Then to get ##f_{xy}## they differentiated ##f_x## with respect to ##y##.
 
Thanks, that makes sense.
 

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