Lo.Lee.Ta.
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My set-up for the integral is right:
2\pi∫0 to 4 of (x)(√(4x) - (2x - 4))dx
= 2\pi∫(2x3/2 - 2x2 + 4)dx
When I Wolfram Alpha the answer, it is 448\pi/15.
The computer HW system counts that answer as correct.
But when I try to take the integral, it's wrong! :(
I did this...:
2\pi(2x5/2/5/2 - 2(x3)/3 + 4x2/4] |0 to 4
= 29.86\pi
...This is not right. But what's the matter with my integration?
Thanks SO much for the help! :)
2\pi∫0 to 4 of (x)(√(4x) - (2x - 4))dx
= 2\pi∫(2x3/2 - 2x2 + 4)dx
When I Wolfram Alpha the answer, it is 448\pi/15.
The computer HW system counts that answer as correct.
But when I try to take the integral, it's wrong! :(
I did this...:
2\pi(2x5/2/5/2 - 2(x3)/3 + 4x2/4] |0 to 4
= 29.86\pi
...This is not right. But what's the matter with my integration?
Thanks SO much for the help! :)