How Is Phase Difference Calculated Between Two Sound Waves?

[jrrodri7]

Homework Statement

Two Loud speakers are placed on a wall 3.79 meters apart. A listener stands directly in front of one of the speakers, 65.6 meters from the wall. The speakers are being driven by the same electric signal generated by a harmonic oscillator of frequency 4010 Hz The speed of sound in Air is 343 m/s. What is the phase difference $$\Delta\Phi$$ between the two waves? (answer in radians)

Homework Equations

y = A sin (kx (+/-) $$\omega$$t

The Attempt at a Solution

I tried finding the wavelength and using trig to find the distance between the observer and speakers...but I'm not sure if it has anything to do with the problem, and I haven't gotten an answer out of this yet...I'm lost. The only thing I know is superposition, but I know that if you just add sin to sin, you don't just get sin, and I don't know how to derive that to see how that works...

HELP!

 

[LowlyPion]

Homework Statement

Two Loud speakers are placed on a wall 3.79 meters apart. A listener stands directly in front of one of the speakers, 65.6 meters from the wall. The speakers are being driven by the same electric signal generated by a harmonic oscillator of frequency 4010 Hz The speed of sound in Air is 343 m/s. What is the phase difference $$\Delta\Phi$$ between the two waves? (answer in radians)

Homework Equations

y = A sin (kx (+/-) $$\omega$$t

The Attempt at a Solution

I tried finding the wavelength and using trig to find the distance between the observer and speakers...but I'm not sure if it has anything to do with the problem, and I haven't gotten an answer out of this yet...I'm lost. The only thing I know is superposition, but I know that if you just add sin to sin, you don't just get sin, and I don't know how to derive that to see how that works...

HELP!

Sure it does. The difference in distance is going to determine what lag there is between the 4010 hz sound waves.