How Is Tension Calculated for a Submerged Accelerating Object?

AI Thread Summary
To calculate the tension in the fishing line for a submerged lead weight with a volume of 0.69x10^-5 m^3 and an upward acceleration of 1.8 m/s^2, one must consider both the gravitational force acting on the weight and the buoyant force due to the displaced water. The mass of the lead weight can be determined using its volume and the density of lead (11.34 g/cm^3). The net force required for the upward acceleration can be calculated using Newton's second law (F=ma), and the buoyant force must be subtracted from the weight's gravitational force. The discussion highlights the importance of applying Archimedes' principle to find the buoyant force, which is equal to the weight of the water displaced by the lead weight. Properly incorporating these forces will yield the correct tension in the fishing line.
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Homework Statement


A lead weight with a volume of 0.69x10^-5 m^3 is lowered on a fishing line into a lake to a depth of 1.0m. What tension is required in the fishing line to give the weight an upward acceleration of 1.8m/s^2?


Homework Equations


T=F-mg F=ma D=mv D of lead= 11.34gcm^3


The Attempt at a Solution


I have tried solving it (first changing density into m, to be compatible with my volume value). Then I found the mass of the lead weight (using the given volume and measured density). But still not sure if I'm going through the proper means to arrive at the tension. Any suggestions?
 
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Where have you used Archimedes' principal that you cite in your title? It tells you that there is an bouyancy force equal to the weight of water with the same volume as the lead weight.
 
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