How Is the Area of a Floating Slab Calculated Using Buoyancy Principles?

  • Thread starter Thread starter walker
  • Start date Start date
  • Tags Tags
    Buoyancy
AI Thread Summary
The discussion centers on calculating the area of a floating plastic slab using buoyancy principles. The user applies Archimedes' principle, establishing that the buoyancy force equals the weight of the swimmer and the slab combined. They derive an initial equation for area A but realize it does not incorporate all the variables specified in the question. A suggested approach involves expressing the mass of the slab in two ways and equating them to eliminate variables, leading to a more comprehensive solution. The conversation emphasizes the importance of correctly incorporating all given parameters in the final formula.
walker
Messages
28
Reaction score
0
Question is: A plastic slab has a thickness of h and a density p_s . when a swimmer of mass m is resting on it, the slab floats in fresh water with its top at the same level as the water surface. find the area of the slab. give your answer in terms of density of water p_w , p_s , h and m

so what I've done is used achimedes principle where all forces are in equilibrium. that is B = Mg

M being the mass of the swimmer and slab of plastic combined

so by setting this equation equal to the buoyancy force in terms of pressure I get: Mg = p_w*g*V where p_w is the density of fresh water and since V equals h*A I can sub for V and get Mg = p_w*g*h*A then i can just solve for A but the answer A = M/(p_w*h) doesn't use all the terms given in the question. am i just reading into the question too much or am i missing something here?
 
Physics news on Phys.org
I got an answer by setting up two equations:

find a statement for the mass of the slab using its density, h and the unknown area.

Find another statement for the mass of the slab using the equation you have above (but call the combined mass "M+m" with M being the mass of the slab).

With two terms for the mass of the slab, set them equal to each other so that M goes away. Then do some algebraic gymnastics and you get an answer with the proper variables.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top