How Is the Horizontal Distance of a Cannon Ball Calculated on a Sloped Surface?

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SUMMARY

The horizontal distance a cannonball travels when fired from an angle θ on a sloped surface is calculated using the formula dx = 2v²cos(o)sin(O + o)/gcos(O), where v is the initial velocity, o is the angle of projection, O is the slope angle, and g is the acceleration due to gravity. The discussion emphasizes the importance of understanding the intersection of the projectile's flight path with the slope's equation. Key trigonometric identities, such as sin(O + o) = sin(O)cos(o) + sin(o)cos(O), are also highlighted as essential for deriving the distance formula.

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  • Understanding of projectile motion principles
  • Familiarity with trigonometric identities
  • Knowledge of basic calculus for analyzing functions
  • Ability to apply kinematic equations in physics
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A cannon ball is fired from an angle o with an intial velocity of v. The hill sklopes down with an angle of O. Prove that the horizontal distance the cannon ball travels is given by dx= 2v2cos(o)sin(O+o)/gcos(O)



2. Equations
sin(O+o)=sin(O)cos(o)+sin(o)cos(O)
d=1/2gt2




The Attempt at a Solution


Please help me! Hopefully the picture helps!
 

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Welcome to PF.

You might want to consider the point at which it hits as the intersection of the function that describes the projectile's flight with the equation that describes the slope of the incline.

For instance for 45 degrees you know that dx = dy.

Or more generally for angle θ you have Dy = tanθ *dx
 

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