How Is the Work Done by Friction Calculated on an Inclined Plane?

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SUMMARY

The work done by friction on a 500 kg crate on a 30° inclined plane, subjected to a horizontal force of 4000 N, can be calculated by first determining the work done by the applied force and the work associated with the change in kinetic energy. The crate moves 3.0 m in 9.2 seconds, with an initial velocity of 1.0 m/s and a final velocity of 2.8 m/s. By calculating the total work done and subtracting the work done against gravity and the change in kinetic energy, the work done by friction can be accurately determined.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of work-energy principle
  • Familiarity with inclined plane physics
  • Basic algebra for calculations
NEXT STEPS
  • Calculate work done by the applied force using the formula W = F × d
  • Learn about gravitational potential energy changes on inclined planes
  • Study the work-energy theorem to relate work done to kinetic energy changes
  • Explore frictional force calculations and their impact on motion
USEFUL FOR

Students studying physics, engineers working on mechanics, and anyone interested in understanding the dynamics of objects on inclined planes.

behzad82
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a 500 kg crate is on a rough surface inclined at 30°. A constant external force
P = 4000 N is applied horizontally to the crate. The force pushes the crate a distance of 3.0 m up the
incline, in a time interval of 9.2 s, and the velocity changes from ν1 = 1.0 m/s to ν2 = 2.8 m/s. The
work done by the friction force is closest to:

I have no idea how to start this. I tried just using the regular work equation or conservation of energy and did not find the answer.
 
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You are posting this in the wrong forum.

Anyway, find the work done by the force, then find the work done to bring it from a lower to a higher region, to increase the velocity, etc. , and just minus off all of them to find the work done to overcome friction.
 

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