How long ago did the wooly mammoth disappear from North America?

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Woolly mammoth bones found in North America indicate that the youngest bones have a radiocarbon activity of about 21% of the original amount. To determine how long ago these animals disappeared, one can use the half-life of carbon-14, which is approximately 5730 years. The discussion suggests that calculating the number of half-lives needed to reduce the carbon-14 to 21% can be done mathematically without needing to derive the decay constant. Both methods of calculation are valid and interconnected, with one being simpler given the known half-life. The consensus is to use the half-life method for a straightforward solution.
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Bones of the wooly mammoth have been found in North America. The youngest of these bones has a 14C activity per gram of carbon that is about 21% of what was present in the live animal. How long ago (in years) did this animal disappear from North America?

I'm struggling with this problem - is it simply a mathematical problem - working out how many half-lives (5730 years) cause 21% to be left?
Or, do i have top work out the Decay constant λ then use ΔN/Δt = -λ N ?

If it is simply a mathematical Can anyone tell me how to do it please.
If I have to find the Decay constant, I'm still stumped on the mathematics involved.

Thanks for any help.

Chawkdee
 
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You just need the ratio of N_now, N_orig and the half life.
The equation is derived here http://en.wikipedia.org/wiki/Half-life

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Hint, estimate how many half lives you would need to get 25% of the c14 left - it's easy to get logs the wrong way around in the calculator
 
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Well, both methods are mathematical! There is no difference between them. The differential equation dN/dt = -λN has an exponentially decaying solution: N(t) = N0e-λt, where the constant N0 is the original amount.

You can easily express this as an exponential function having base 2 instead of base e. That will tell you the relation between the half-life and λ. That is how the two methods are related. That having been said, since you already know the half-life, you can probably use the first method you suggested.
 
Thanks a lot - great help!
 
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