How long does it take a Capacitor to charge to 80% of its final value?

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Homework Help Overview

The discussion revolves around a circuit containing an inductor, resistor, and capacitor in series, focusing on determining the time it takes for the capacitor to charge to 80% of its final voltage value.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the voltage equation for the capacitor and the concept of time constants. Questions arise regarding the limit of the voltage as time approaches infinity and how to numerically or graphically determine the time at which the capacitor reaches 80% of its final value.

Discussion Status

Some participants have provided guidance on finding the limit of the voltage function and suggested methods for solving the equation. There is ongoing exploration of the calculations involved, with participants sharing their attempts and corrections to their previous calculations.

Contextual Notes

Participants note the lack of certain values, such as the current, and question the implications of their findings in an exam context. There is also mention of potential confusion regarding the numerical results obtained during the discussion.

MarkH748
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Homework Statement



I have a a circuit with an inductor, a resistor and a capacitor in series. I have analyzed the circuit and gotten an equation for the voltage across the capacitor to be.

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Homework Equations



Vc(t) = 10 + (20/3)e^-5t - (50/3)e^-2t

The Attempt at a Solution



I assume its something to do with time constants but there isn't any that give me 80% is there? Also my electronics isn't that great so I don't know how to deal with the inductor.

Any help would be greatly appreciated.

Mark.
 
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What is the limit of Vc when tends to infinity? You need to determine the time t when Vc is 80 percent of this value. You can solve the equation only numerically, but the result will be close to 0.95 s.

ehild
 
I'm still unsure. Do I say @ t = infinity, Vc = 10 - 700I ? I don't have a vlue for I though. Do I need one? I'd also be interested to know how you estimated 0.95s. Could I write in an exam, "By observation, t = 0.95s" ? or would that be meaningless?
 
Vc(t) = 10 + (20/3)e^-5t - (50/3)e^-2t

This is the equation which gives the voltage of the capacitor as function of time. I do not know if you have learned about differential equations or not, but it is the solution of the circuit equation - a second order differential equation for the charge on the capacitor.

Now you have no other task, find the limit of the Vc(t) function when the time goes to infinity. What happens then with the exponential functions?

You can solve an equation numerically by trying different values, or with some kind of iteration. You can also solve it graphically: Plot it out.

ehild
 
I think I understand now. When t -> infinity, Vc = 10 V (this is correct?). So I need to find a value for t for when Vc is 8 volts using one of the methods you mentioned?

edit: this gives me t = 3.6188.
 
Last edited:
Yes, you can find t when Vc is 8 V. But your t is too big. Try to plug in. How did you get it?

ehild
 
Ah, I put V equal to 2 volts by accident. Putting it equal to 8 gives me t = 0.9047 s. Thanks for your help.
 
You are welcome.

ehild
 

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