How Long for Potential Difference to Reach 50 Volts in an Oscilloscope?

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SUMMARY

The discussion focuses on calculating the time required for a potential difference of 50 volts to be reached across the deflection plates of an oscilloscope, given a 100-volt supply through a 900-ohm resistor. The deflection plates measure 10 cm by 2 cm with a gap of 1 mm, and the problem is modeled as an RC circuit. The key equation used is q = C * (ΔV), where C represents the capacitance of the plates. The solution involves deriving the charging equation for the capacitance to determine the time constant.

PREREQUISITES
  • Understanding of RC circuits and time constants
  • Knowledge of capacitance calculation for parallel plate capacitors
  • Familiarity with voltage and charge relationships in capacitors
  • Basic algebra for solving exponential equations
NEXT STEPS
  • Study the derivation of the charging equation for capacitors in RC circuits
  • Learn how to calculate capacitance for parallel plate capacitors
  • Explore the concept of time constants in electrical circuits
  • Examine the behavior of voltage across a capacitor over time during charging
USEFUL FOR

Students in electrical engineering, physics enthusiasts, and anyone studying circuit analysis or oscilloscope operation will benefit from this discussion.

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Homework Statement


The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is suddenly applied to the initially uncharged plates through a 900 ohm resistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 50 volts?


Homework Equations


q=c*(delta_V)


The Attempt at a Solution


There has to be an equation that I am missing or need
 
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The whole problems converts into a RC circuit.
Find the expression for the charging of the capacitance.
 

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