How many 4-digit numbers can be formed with a limited number of digits?

AI Thread Summary
The discussion revolves around calculating the number of 4-digit numbers that can be formed using no more than two different digits. Three cases are identified: all four digits being the same, three digits being the same with one different, and two pairs of digits being the same. There is a debate about whether leading zeros are permissible, with some participants suggesting that they should be allowed to maximize combinations. However, it is also noted that if leading zeros are not allowed, the first digit must be non-zero. The conclusion emphasizes the importance of clarifying the rules regarding leading zeros for accurate calculations.
xiphoid
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Homework Statement


how many 4 digit numbers are there which do not contain more than 2 different numbers?


Homework Equations






The Attempt at a Solution


all can contain the same digit
any 3 out of the 4 places can be occupied by the same digit
and
any 2 out of the 4 places can be occupied by the same digit
 
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xiphoid said:

Homework Statement


how many 4 digit numbers are there which do not contain more than 2 different numbers?


Homework Equations






The Attempt at a Solution


all can contain the same digit
any 3 out of the 4 places can be occupied by the same digit
and
any 2 out of the 4 places can be occupied by the same digit


You are on the right track, think about it this way. You have a choice of choosing the numbers from 1 to 9 and then you have three cases:

1. the case where all 4 numbers are the same number as you chose

2. the case where 3 numbers are the same number as you chose as well as you have to choose another number that's different from the other three

3. the case where 2 numbers are the same number as you chose and you have to choose 2 other numbers where they are different from each other and different from the other 2 you previously chose

Does that make sense?
 
leej72 said:
You have a choice of choosing the numbers from 1 to 9 and then you have three cases.
Shouldn't that be digits from 0 to 9 (a total of 10 possible digits)?
 
rcgldr said:
Shouldn't that be digits from 0 to 9 (a total of 10 possible digits)?

Probably yes, but (presumably) the first (left-most) digit cannot be 0. (Since this is not made clear, if I were doing the problem I would solve both versions.)

RGV
 
As you mention, it's not clear if leading zeroes are allowed, like a combination lock with 4 digits. I would assume they are allowed, since otherwise it eliminates all the combinations such as 0xxx, 00xx, 000x, 0000.
 
rcgldr said:
Shouldn't that be digits from 0 to 9 (a total of 10 possible digits)?

Yes that was a typo, I did mean from 0 to 9 but I am not too sure if the first number would be allowed to be a 0. I would personally think otherwise, not letting the first number to 0
 
as per the answer given, you will need to consider both the cases!
 
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