How Many 4-Digit Permutations Greater Than 5364 Can Be Formed?

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The discussion focuses on calculating the number of 4-digit permutations greater than 5,364 using the digits 1, 2, 3, 5, 7, and 8. For part a, where repetition is allowed, the correct total is 552 permutations, achieved by analyzing different cases based on the first digit. For part b, where repetition is not allowed, the total is 150 permutations. The initial attempts at solutions did not account for restrictions based on the digits placed in the first and second positions. Understanding these restrictions is crucial for accurate calculations.
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Homework Statement


8. Using the digits 1, 2, 3, 5, 7, 8 how many 4 digit numbers greater than 5,364 could be constructed if:
a) Repetition of the digits is allowed?
b) Repetition of the digits is not allowed?

Homework Equations


The Attempt at a Solution


for part a:
2*6*6*6 (for 8 and 7 as the first digit)
+
1*4*2*3 (for 5 as the first digit)

But it is incorrect :(

Correct answer is 552 for part a and 150 for part b
 
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For part a), consider 3 cases: The first digit > 5, the first two digits being 5 and 3, the first digit being 5.

If the first digit is 5 and the second 3, then this puts a restriction on the last two. If the first digit is 5 and the second > 3, then there is no restriction on the last two. This is what your answer does not take into consideration.
 
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