How many Amp turns around the Earth for this flux density?

Click For Summary
SUMMARY

The calculation for creating an electromagnetic field equivalent to Earth's magnetic field strength of 0.5 Gauss requires approximately 500 million ampere-turns. Using AWG #0 copper wire, the total length of wire needed would be around 80 billion miles, weighing approximately 1.35 quintillion pounds. The power required to drive this coil is estimated at 9.45 million gigawatts, which exceeds the current global electrical generating capacity by a factor of 60. This analysis indicates that constructing Earth-sized Helmholtz coils is not feasible with current resources.

PREREQUISITES
  • Understanding of electromagnetism principles
  • Familiarity with ampere-turns and magnetic field calculations
  • Knowledge of wire gauge specifications, specifically AWG #0
  • Basic grasp of global electrical generating capacity metrics
NEXT STEPS
  • Research the principles of electromagnetism and magnetic field strength calculations
  • Explore the properties and applications of AWG #0 copper wire in electrical engineering
  • Investigate the feasibility of large-scale electromagnet designs and their energy requirements
  • Analyze global electrical generation methods and their capacity limitations
USEFUL FOR

Electrical engineers, physicists, and researchers interested in electromagnetism and large-scale energy systems will benefit from this discussion.

Clark Magnuson
Messages
9
Reaction score
3
Someone is asking me how much current in a loop of wire the diameter of the Earth to make the same level of magnetism the Earth has?

I hope I am asking this correctly.
TIA
Clark
 
  • Like
Likes   Reactions: jrmichler
Engineering news on Phys.org
It's been almost 20 years since I calculated an electromagnet, but I'll try anyway.

Earth's magnetic field strength is about 0.5 Gauss = 0.5E-4 Tesla
Length = 13,000,000 meters (diameter of Earth)
Mu = 4 PI E-7 Weber/ampere-meter (permeability of free space, might be way off considering the iron and nickel in Earth's core)

NI = 0.5E-4 X 13E6 / 4 PI E-7 = 500,000,000 ampere-turns. I welcome any confirmation and/or correction.
 
  • Like
Likes   Reactions: anorlunda
Let's see how to build a coil to cancel that field. Since I don't expect an implementation. I'll be rounding off values here.

Choose AWG #0 Copper wire with a diameter over insulation of 0.5inch.

Dia. 0.5in. = 24 Turns/Ft. = 126 720 Turns/mile
Res Ohm/1000Ft = 0.1 Ohms = 5.28 0.528 Ohms/Mile
Weight = 3.13ft/pound = 5280/3.13 = 1687lb/mi
Current rating 150A

5E8 Ampere-Turns needed
Earth Circumference = 24000 Miles

5E8AT/150A = 3.3E6 Turns * 24000 = 8E10 miles of wire
3.3E6/126720 Turns per mile = one-layer winding 26.3 Miles wide

3.3E6 Turns * 24000 = 8E10 miles of wire
8E10 * 16871lb/mi = 1.35E15 pounds of wire

8E10 miles * 5.28 0.528 Ohms per mile = 4.224E11 10 Ohms
150A * 4.224E11 10 = 6.3E1312[/color] Volts to drive the coil

With 1.35E15 pounds of Copper wire needed and Global Copper production of 5E10 pounds per year, you would need 27000 years to mine the Copper.

It looks like Earth-sized Helmholtz coils won't be in our lifetime. :wink:

Cheers,
Tom
 
Last edited:
  • Like
Likes   Reactions: jrmichler
Clearly, we now need a power calculation.

6.3E13 volts X 150 amps = 9.45E15 watts = 9,450,000 GW.
Total world electrical generating capacity = 15,856 GW (https://www.cia.gov/library/publications/the-world-factbook/rankorder/2236rank.html)

The total world generating capacity is only short by a factor of 600.
 
  • Like
Likes   Reactions: Tom.G
Correction to posts #3 and #4.[/color]

Tom.G said:
...I'll be rounding off values here.
It turns out I did more than round off, I made a power-of-10 error in the resistance. That made the needed Voltage too high by a factor of 10.
My post #3 has been corrected.

Unfortunately, that also impacted @jrmichler post #4, making it too high by a factor of 10. Sorry. :cry:
jrmichler said:
Clearly, we now need a power calculation.

6.3E13 volts X 150 amps = 9.45E15 watts = 9,450,000 GW.
Total world electrical generating capacity = 15,856 GW (https://www.cia.gov/library/publications/the-world-factbook/rankorder/2236rank.html)

The total world generating capacity is only short by a factor of 600.
The updated values would be 945,000 GW and generating capacity short by a factor of 60.
 
  • Like
Likes   Reactions: jrmichler

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
4K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 28 ·
Replies
28
Views
6K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K