Angular momentum is a vector, so alegedly it has 3 degrees of freedom.(adsbygoogle = window.adsbygoogle || []).push({});

It has never been formally told me, but I noticed angular momentum is taken as two seperate magnitudes and not three. i.e. in quantum mechanics there's an operator for [itex]\bf{L}^2[/itex] and for [itex]L_z[/itex] and this should be enough.

My question is whether knowing a vector's magnitude (it's "absolute value") and one of it's components is sufficient to determine the othertwocomponents (i.e. [itex]L_x[/itex] and [itex]L_y[/itex])

I guess that for ageneral vectorthis would be a NO. but specifically angular momentum is a cross product... and I think it matters.

Thanks in advance.

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# Homework Help: How many degrees of freedom does angular momentum have?

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