How many ice cubes were added to cool the pool to 17°C?

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SUMMARY

The physics problem involves calculating the number of ice cubes needed to cool a 156-liter pool of water from 26°C to 17°C using ice cubes of mass 30 g each at 0°C. The specific heat of water is 1.0 cal/g°C, the specific heat of ice is 0.5 cal/g°C, and the latent heat of fusion is 80 cal/g. The correct approach requires accounting for both the heat absorbed during melting and the subsequent heating of the resulting water to 17°C, leading to a total heat exchange calculation that determines the number of ice cubes needed.

PREREQUISITES
  • Understanding of heat transfer principles, specifically Q=mc(ΔT)
  • Knowledge of specific heat capacities of water and ice
  • Familiarity with latent heat of fusion
  • Basic algebra for solving equations
NEXT STEPS
  • Review the concept of latent heat and its application in phase changes
  • Practice problems involving heat transfer calculations in isolated systems
  • Explore the relationship between mass, specific heat, and temperature change
  • Investigate the effects of different initial temperatures on heat exchange scenarios
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in practical applications of heat transfer principles in real-world scenarios.

cyberdx16
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Homework Statement


Trying to beat the heat of summer, a physics grad student went to the local toy store and purchased a child's plastic swimming pool. Upon returning home, he filled it with 156 liters of water at 26°C. Realizing that the water would probably not be cool enough, he threw ice cubes from his refrigerator, each of mass 30 g, into the pool. (The ice cubes were originally at 0°C.) He continued to add ice cubes until the temperature stabilized at 17°C. He then got in the pool.

The density of water is 1000 kg/m3, the specific heat of water is 1.0 cal/g °C, the specific heat of ice is 0.5 cal/g °C, and the latent heat of fusion of water is 80 cal/g.

How many ice cubes did he add to the pool to get the temperature to 17°C? (Consider the pool and ice cubes an isolated system.)

Homework Equations



Q=mc(DeltaT)
Qwater/Qice=# of ice cubes

The Attempt at a Solution



Mass water=1000*.156=156kg
Qwater=156000g(1.0 cal/g*degree Celsius)(17-26)=-1404000cal
QIce=30g(.5 cal/g*degree Celsius)(17-0)=255cal

now do i neglect the negative in Qwater? so then i would get 1404000cal/255cal=5505.88cubs but is not the correct answer

I don't understand what i have to do with the latent heat of H2O fusion(80cal/g)
 
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All of the cubes melted. Each gram of ice absorbed 80 cal/gm of heat as it melted and THEN the resulting WATER warmed up to 17 degrees. In fact, the heat capacity of ice has nothing to do with the problem.
 
Dick said:
All of the cubes melted. Each gram of ice absorbed 80 cal/gm of heat as it melted and THEN the resulting WATER warmed up to 17 degrees. In fact, the heat capacity of ice has nothing to do with the problem.

I still have no clue wtf is going on... now would i use the equation Q=mL for the ice? that would give me 2400cal... Then take the Qw=1404000/Qice=2400? but that gives me 585, which is not the correct answer
 
There are two parts in Qice. One of them you just computed. To get the other one you have to heat the melted water up 17 degrees. Then you have to add them.
 
alright gotcha! i guess i didnt take into consideration that ice metals and turns to h20 (l) and heats up to 17C
 

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