How Many Integers Satisfy This Inequality?

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Discussion Overview

The discussion centers around the number of integers that satisfy the inequality $$|||x+9|-18|-98| \le 82$$. Participants explore different approaches to solving the inequality, including various cases based on the absolute values involved.

Discussion Character

  • Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant suggests that by assuming \(x + 9 \ge 0\), they derive the inequality \(-82 \le |x - 9| - 98 \le 82\), leading to a conclusion of 165 solutions.
  • Another participant proposes that if \(|x + 9| \le 0\) is considered, it also results in 165 solutions, thus totaling 330 solutions.
  • However, a later reply indicates a different count, stating they arrived at 332 solutions, prompting a request for verification of the correct solution.

Areas of Agreement / Disagreement

Participants express differing counts of solutions, with some asserting 330 and others claiming 332. The discussion remains unresolved regarding the correct number of solutions.

Contextual Notes

Participants have not fully detailed their assumptions or the steps leading to their conclusions, leaving some mathematical reasoning and conditions implicit.

Who May Find This Useful

Individuals interested in mathematical inequalities, particularly those involving absolute values, may find the discussion relevant.

anemone
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How many integers satisfy the following relation?

$$|||x+9|-18|-98| \le 82$$
 
Last edited:
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anemone said:
How many integers satisfy the following relation?

$$|||x+9|-18|-98| \le 82$$

if we put x + 9 >= 0 we get

- 82 <= | x- 9 | - 98 <= 82

so 165 solutions as |x -9| - 98 can be atleast -98

similarly if we put | x+ 9| <= 0 so 165 solutions

so 330 solutions
 
kaliprasad said:
...

so 330 solutions

BUT...I got 332.
 
anemone said:
BUT...I got 332.

I would like to have a look at the correct solution
 
My solution:

We have two cases to consider here, one is when $x+9\ge 0$ and the other is when $x+9< 0$.If $x+9\ge 0$ (i.e. $x \ge -9$), then the inequality becomes

$$||x+9-18|-98| \le 82$$

$$||x-9|-98| \le 82$$

[TABLE="class: grid, width: 500"]
[TR]
[TD]i.[/TD]
[TD]ii.[/TD]
[/TR]
[TR]
[TD]Now, let $x-9\ge 0$ (i.e. $x \ge 9$), we have[/TD]
[TD]Now, let $x-9< 0$ (i.e. $x \ge 9$), we have[/TD]
[/TR]
[TR]
[TD]$$|x-9-98| \le 82$$

$$|x-107| \le 82$$

$$-82 \le x-107 \le 82$$

$$25 \le x \le 189$$[/TD]
[TD]$$|-(x-9)-98| \le 82$$

$$|-x-89| \le 82$$

$$-82 \le -x-89 \le 82$$

$$-171\le x \le -7$$[/TD]
[/TR]
[TR]
[TD]View attachment 1395

The number of integers that satisfy the aforementioned relation is thus $165$.[/TD]
[TD]View attachment 1396

The number of integers that satisfy the aforementioned relation in this particular case is thus $2$.[/TD]
[/TR]
[/TABLE]

But if $x+9< 0$ (i.e. $x<-9$), then the inequality becomes

$$||-x-9-18|-98| \le 82$$

$$||-x-27|-98| \le 82$$

[TABLE="class: grid, width: 500"]
[TR]
[TD]i.[/TD]
[TD]ii.[/TD]
[/TR]
[TR]
[TD]Now, let $-x-27\ge 0$, we have[/TD]
[TD]Now, let $-x-27< 0$, we have[/TD]
[/TR]
[TR]
[TD]$$|-x-27-98| \le 82$$

$$|-x-125| \le 82$$

$$-207 \le x \le -43$$[/TD]
[TD]$$|-(-x-27)-98| \le 82$$

$$|x-71| \le 82$$

$$-11\le x \le 153$$[/TD]
[/TR]
[TR]
[TD]The number of integers that satisfy the aforementioned relation is thus $165$.[/TD]
[TD]The number of integers that satisfy the aforementioned relation in this particular case is thus $2$.[/TD]
[/TR]
[/TABLE]

Therefore, the total number of integers satisfy the relation $$|||x+9|-18|-98| \le 82$$ is $165+3+165+2=335$.

Hey kaliprasad, I'm sorry because according to my previous reply, I told you the answer that I've gotten was 332, which isn't the correct answer. :o
 

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