How many people can the raft hold physics problem

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To determine how many people a raft made of 10 logs can hold before submerging, the buoyant force must be calculated based on the volume of water displaced by the logs. Each log has a diameter of 30 cm and a length of 5.5 m, leading to a total volume that can be used to find the weight of the displaced water. The specific gravity of the wood is 0.60, which helps in calculating the weight of the logs themselves. By equating the total weight of the logs and the weight of the people to the buoyant force, the maximum number of people can be derived. The key is to ensure the total weight does not exceed the buoyant force before the raft starts to sink.
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CAN ANYONE HELP ME, PLEASE ! I DON'T KNOW HOW TO SOLVE THIS PROBLEM

A raft is made of 10 logs lashed together. Each is 30cm in diameter and has a length of 5.5m. How many people can the raft hold before they start getting their feet wet,assuming the average person has a mass of 70 kg? Do not neglect the weight of the logs! Assume the specific gravity of wood is 0.60.

SG=0.60
r=1/2*30=15cm

I know
F/A = mg/A
F= mg =pAHg were p-->density
p=m/v
pressure=P=F/A
 
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Hint: What's the buoyant force acting on a completely submerged log?
 


The boyanty Force is:

Fb = F2 - F1
pfgA(h2-h1)
pfgAh
pfgV

I don't know how to solve please help !
 


The buoyant force is the weight of the displaced fluid. How much water does a submerged log displace?
 

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