How many right triangles can you create with given coordinates?

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SUMMARY

The discussion focuses on determining the number of right triangles that can be formed from five given coordinates: (0, 0), (2, 0), (1, 1), (1, -1), and (3, -1). The user initially calculates combinations using the formula C(5, 2) = 10 to find pairs of points but seeks a simpler method. A key insight shared is that the fastest way to verify right angles is by calculating the slopes of the lines connecting the points, as perpendicular lines have slopes that are negative reciprocals of each other.

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  • Understanding of coordinate geometry and Cartesian coordinates
  • Knowledge of the concept of right triangles and their properties
  • Familiarity with calculating slopes between two points
  • Basic combinatorial mathematics for calculating combinations
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  • Study the properties of right triangles in coordinate geometry
  • Learn how to calculate slopes and determine perpendicular lines
  • Explore combinatorial mathematics, specifically combinations and permutations
  • Investigate algorithms for efficiently checking triangle properties in computational geometry
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This discussion is beneficial for students in geometry, mathematicians interested in combinatorial problems, and software developers working on algorithms related to geometric computations.

Дьявол
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Hello!
I have one question.
I have given 5 coordinates:
0 0
2 0
1 1
1 -1
3 -1

The question is how many right angles can I create with these coordinates?
I know one way out, but it is pretty complicated.
C52=5!/(2!*3!)=5*4*3!/(2!*3!)=10
And try every single combination (finding the sides of the triangles, there are 10 of them). Is there any simpler way?

Thanks in advance.
Regards.
 
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I'm not sure how you tested to see if the triangles are right, but the fastest way is to find the slope of the lines between each two points. Perpendicular lines have slopes which are negative reciprocals of each other.
 
you never made sure that the angles you'll get will be all right angles.
 

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