atyy
Science Advisor
- 15,170
- 3,379
vanhees71 said:Now to the argument that it's not the state preparation which determines the outcome of measurements. This is pretty absurd, or do I misunderstand this statement completely? Even in classical physics, of course the preparation of an experiment determines the outcome of measurements. This is trivial, isn't it? The difference in quantum theory is that there are indetermined observables even when we know the exact (pure) state of the system, as with our entangled photon pair.
In both classical and quantum physics, there is the possibility that the state preparation and measurement procedure determines the outcome.
Another way to see the problem is that even if one says that state preparation determines measurement outcomes, the problem is that the quantum formalism says that measurement is a form of state preparation. If there an initial state preparation, followed by measurement A, followed by measurement B, there is more than one state preparation procedure, so it is unclear which state preparation procedure is the "cause" for the outcome of measurement B.
vanhees71 said:If I prepare photons in the described polarization-entangled state, quantum theory predicts the probabilistic properties of measurements of the single photons' polarizations uniquely, including correlations of (independent and local) measurements by Alice and Bob, when they compare their measurement protocols, provided the measurements are accurate enough in time resolution to be able to always associate the photons belonging to one entangled pair. Of course, the polarization state of both photons is maximally indetermined, but for each measurement of the polarization of Alice's and Bob's photons, we can predict the corresponding conditional probabilities. The same holds for the prediction of the interference pattern, which reflects the probabilities to detect photons on the screen behind the double slit, and as far as I know these probabilistic predictions of QT are very well (i.e., with very high statistical significance) agreeing with the findings in experiments. Why then, can't I then conclude that it is simply the preparation in this entangled state by parametric down conversion that determines the (probabilistic) behavior predicted by QT and confirmed by experiment? If I can't, I don't know, how to make sense of the notion of states in quantum theory at all, but also this contradicts the experience that we very well know how to use quantum theory to describe the empirical findings when performing such experiments.
Yes, quantum mechanics works. The question is whether quantum mechanics respects Einstein causality. Let me try to extract what I think is the essence of the Cavalcanti and Lal paper. The two important definitions are:
(RCC) Relativistic causality: the cause of an event is in the past light cone of the event
(FP) Common cause of a correlation: if z is the common cause of a correlation between A and B, then P(A,B|z) = P(A|z)P(B|z)
It can be shown that Bell's local causality, which is understood to be equivalent to Einstein Causality, is essentially RCC + FP. Quantum mechanics does not obey local causality, so either RCC or FP or both must be rejected. Presumably we are trying to keep RCC, since that is essential for Einstein Causality. If we reject FP, then correlations cannot have a common cause. It may be possible to redefine what it means for a correlation to have a common cause, but FP is the definition of common cause for all classical causality including Einstein Causality, so if you redefine common cause, one would be redefining Einstein causality.
I would say that in a minimal interpretation, relativistic quantum mechanics does not need Einstein Causality for correlations. Only signal locality is needed, ie. classical information cannot travel faster than light. The requirement that spacelike separated observables commute is closer to signal locality, because measurement of an observable is something that extracts a classical outcome from a quantum state.
Last edited:
