How Much CO2 Can 1.90kg of KO2 Absorb?

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The discussion focuses on calculating the amount of CO2 that can be absorbed by 1.90 kg of KO2 through a series of chemical reactions. The provided calculations utilize molar masses, with KO2 at 71.10 g/mol and CO2 at 44.01 g/mol, leading to a final absorption estimate of 0.588 kg of CO2. Participants confirm that including water in the reaction does not affect the final result, as the molar ratios remain unchanged. The calculations are verified, and the methodology is deemed correct. The final conclusion is that 1.90 kg of KO2 can absorb approximately 0.588 kg of CO2.
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4KO2 + 2H2O --> 4KOH + 3O2
2KOH + CO2 --> K2CO3 + H2O

What mass of CO2 in kg can be absorbed by 1.90kg of KO2?

Molar masses are KO2 = 71.10g, CO2 = 44.01g
------------

So, would this make sense?
1.90kg KO2 x 1/71.10 x 4/4 x 56.11 = 1.499kg
then take that...
1.499g x 1/56.11 x 1/2 x 44.01 = 0.588kg (as the answer)



the 56.11 I had to figure out- they gave me the other molar masses...?

Thank you!
 
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Why do you use water in reaction equations?

4KO2 + 2CO2 -> 2K2CO3 + 3O2

But it doesn't change final result, as molar ratio of 4KO2 and 2CO2 is identical. 0.588 is OK.
 

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