How Much EDTA Is Needed to Neutralize Calcium in a 44-Gallon Drum?

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To neutralize calcium in a 44-gallon drum containing 20 mg/L of calcium, the required mass of EDTA can be calculated using stoichiometry. First, determine the total mass of calcium in the drum by converting the concentration from mg/L to grams for the total volume. The molecular weight of calcium is 40.078 g/mol, and since one mole of EDTA complexes with one mole of calcium, the mass of EDTA needed can be derived from the moles of calcium present. The calculations involve converting gallons to liters and applying the appropriate molar conversions for both calcium and EDTA. This approach will yield the exact amount of EDTA required to fully complex the calcium in the waste.
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Homework Statement



Ethylene diamine tetra-acetic acid (EDTA) is a water-soluble compound that readily combines with metals, such as calcium, magnesium, and iron. The molecular formula for EDTA is C10N2O8H16. Assume one EDTA molecule complexes (associates with) one metal atom.

A factory produces an aqueous waste that contains 20 mg/L calcium and collects the waste in 44-gallon drums. What mass of EDTA would be need to be added to each drum to completely complex all of the calcium in the barrel.



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The Attempt at a Solution


I'm really not sure how to go about this one, i started off trying a few things but it ended up at a dead end...here's what I got so far:

0.02 g/L * 1 mol Ca / 40.078 g Ca * X mol EDTA / 1 mol Ca * 294.24 g EDTA / 1 mol EDTA

I realized this wasn't getting me any closer to an answer so that's why I'm asking for any help you guys can offer.
 
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Calculate number of moles of Ca in 44 gallons.
 
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