How Much Energy Does a Refrigerator Use in a Single Day?

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Homework Help Overview

The discussion revolves around calculating the energy consumption of a refrigerator, specifically focusing on a freezer with a given coefficient of performance and annual energy usage. Participants are tasked with determining daily energy use and the maximum mass of water that can be frozen in a day.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate annual energy usage to daily consumption but initially miscalculates the conversion. Participants discuss unit conversions between kilowatt-hours and joules, and clarify misunderstandings regarding the calculations.

Discussion Status

Participants are actively engaging with the problem, providing clarifications on unit conversions and addressing misconceptions. There is a productive exchange of ideas, with some participants offering corrections and guidance on the calculations.

Contextual Notes

There is a note regarding the conversion of energy units, specifically the relationship between kilowatt-hours and joules, which is central to the discussion. The original poster expresses confusion about the calculations, indicating a need for further exploration of the concepts involved.

fiziks09
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Homework Statement


A freezer has a coefficient of performance of 6.30. It is advertised as using electricity at a rate of 457kWh/yr.
a)On average how much energy does it use in a single day?
b) What maximum mass of water at 20.0 degree celsius could the freezer freeze in a single day.

NOTE: One kilowatt hour is an amount of energy equal to running a 1-kW appliance for one hour


Homework Equations


COP = Q / W


The Attempt at a Solution


I tried to use comparison like so;

if 457kWh is the rate for 365 days
then xkWh is the rate for 1 day

This gives me 1.25 J which is very wrong.

Please can i get clues on how to start or what to do on the "A" part of the question. It's really twisting my head..thanks a lot for your help..
 
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Hi fiziks09! :smile:

What you have is 1.25 kWh, which is 1250 Watt times 1 hour.
This is not 1.25 J, which is 1.25 Watt times 1 second.

You'll need to convert the unit...
 
okay..
but converting the unit still gives a wrong answer...
 
How did you convert it?
 
okay i might have misunderstood. I'm so sorry..what conversion is being made?
is it from kWh to Joules or what? if so how so??
 
Allright i got it now..
since 1kWh = 3.6MJ (which is 3600000J)

1.25kWh X 36000000 = 4.5 X 10^6 Joules..

thanks for the help...
 
Good! :smile:
 

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