2. Hubert drags a 55 kg box over a rough surface of a dock with a constant force of 100N acting at an angle of 15 degrees to the horizontal. The box moves in a straight line for a distance of 6m. Friction acts at an opposite direction to the block and it is 75N. Calculate the work done to move the box? How much energy is dissipated as heat via friction? What is the final velocity of the box?(adsbygoogle = window.adsbygoogle || []).push({});

Ok so i started W=Fd

Would the force be the forces in the x direction? ie: 100cos15 - 75N ?

Which would give W = (100cos15 - 75) x 6 = 129.6Joules ??

Would that also be the energy dissipated as heat?

If so I could then use that to find the final velocity with E=1/2mv^2

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# How much energy is dissipated as heat via friction?

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