How much falling water to generate 3KW

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To generate 3 kW of electrical energy using a 100% efficient turbine generator with a maximum height drop of 5 meters, the change in potential energy must be calculated. The formula for potential energy is mgh, where g is the acceleration due to gravity (9.81 m/s²) and h is the height (5 m). This results in 49.05m joules of energy. To determine the mass flow rate needed, one must convert 3 kW into joules per second and equate it to the potential energy formula. Understanding these calculations is essential for assessing the feasibility of generating the desired power output from falling water.
multivits
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Hello Forum
How much falling water would I need to potentially generate 3 KWatts (240 ACV @ 13 A) of electrical energy?

Assume we have 100% efficient electrical turbine generator.

Our location is residential so the height drop is restricted to say 5 meters max, the lower the better.


TIA

Multivits
 
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The change in potential energy in a 5 m height is mgh= m(9.81)(5)= 49.05m joules. How many Joules are there in 3 kw?
 

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