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thephysicsman
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Homework Statement
A silicon wafer that is 200 um thick has no front reflection, 30% back reflection and absorption coefficient [tex]\alpha=39.9 cm^{-1}[/tex]. What is the flux absorbed?
Homework Equations
Beer's absoorption law:
[tex]\Phi(x) = \Phi_0 e^{-\alpha x}[/tex]
The Attempt at a Solution
[tex]\Phi(0.02 cm) = \Phi_0 e^{-39.9 cm^{-1} \cdot 0.02} = 0.45 \cdot \Phi_0[/tex]
This means that the absorbed flux is [tex]0.55 \cdot \Phi_0[/tex]
Then we take into consideration the reflection. 30% out of the remaining 45% of [tex]\Phi_0[/tex] is reflected, that is 13.5%. 55% of this is absorbed, that is 0.55*0.135 = 7.4%.
In total, 55% + 7.4% = 62.4% is absorbed.
Is this correct?