How Much Force Does a Catcher's Mitt Experience When Catching a Fastball?

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To determine the average force on a catcher's mitt when catching a fastball at 43 m/s, the momentum of the ball (0.15 kg) is calculated to be 6.45 kg·m/s. The average force can be found using the equation Fav = deltap / delta t, where deltap is the change in momentum. To estimate the time interval for the mitt's movement, kinematics and Newton's 2nd law can be applied. The discussion emphasizes the importance of understanding acceleration and work done in solving the problem. Applying these principles will lead to a clearer solution for the average force experienced by the mitt.
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A baseball catcher is catching a fastball that is thrown at 43 m/s by the pitcher. If the mass of the ball is 0.15 kg and if the catcher moves his mitt backward toward his body by 8.0 cm as the ball lands in the glove, what is the magnitude of the average force acting on the catcher's mitt? Estimate the time interval required for the catcher to move his hands.


deltap = mv

43m/s * 0.15kg = 6.45 kgm/s = deltap = Fav * delta t

I'm stuck here and I don't know where to go. I'm assuming acceleration is involved but I don't know how to apply it to the problem. Appreciate it if anybody could help, thanks.
 
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You can find the acceleration of the ball using kinematics. Then use Newton's 2nd law. Or you could consider the work done by the catcher.

[Please use Intro Physics for these kinds of problems!]
 
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