How Much Force is Needed to Balance a Wheelbarrow Load?

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SUMMARY

The discussion centers on calculating the force required to balance a wheelbarrow load weighing 20 N positioned 40 cm from the wheel. Using the torque equation, τ = F * r * sin(θ), the torque from the load is determined to be 8 N·m. The force applied at the handles, located 120 cm from the wheel, must equal 6.67 N to achieve balance. The discussion clarifies that the torque balance equation is essential for solving the problem, emphasizing the importance of understanding torque in static equilibrium scenarios.

PREREQUISITES
  • Understanding of torque and its calculation using τ = F * r * sin(θ)
  • Basic knowledge of static equilibrium and the conditions for balance
  • Familiarity with units of force (Newtons) and distance (meters)
  • Ability to manipulate algebraic equations to solve for unknowns
NEXT STEPS
  • Study the principles of static equilibrium in physics
  • Learn about the concept of torque and its applications in mechanical systems
  • Explore real-world applications of torque in engineering and design
  • Investigate the effects of varying load distances on required balancing forces
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and anyone interested in understanding the mechanics of levers and balance in practical applications.

kathyt.25
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Homework Statement


If the load placed in the wheel barrow weighs 20 N and is 40 cm
from the wheel, what force must be applied to the handles at a
distance of 120 cm in order to balance the load?


Homework Equations


Tau = F r Sin(theta)


The Attempt at a Solution


Im really just guessing on how to do this, but here's my attempt..

Tau of load = (20N)(0.4m)Sin90
= 8N

therefore,
8N = (F)(1.2m)Sin90
6.67N = F --> Thats my answer
 
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The question is not very clear - what does "40 cm from the wheel" mean? If it means the force of gravity vector from the load center of mass passes a minimum of 40 cm from the center of the wheel, then your solution is correct. Perhaps a better way to understand it is to begin with the big picture:
Sum of Torques = I*α = 0 since there is not angular acceleration.
20*.4 - F*1.2 = 0
 

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