schonovic said:
Ryan_m_d are you telling me that even if i had complete fusion down to fusing to iron nuclei I couldn't get away with pulling this off?
Yep. You have a rocket, a rocket of the very worst kind, a single stage rocket. You're screwed.
Let's take a little walk down science fiction woo-woo lane. Suppose you want to send a colony ship to some star. The ship comprises the colonists, an environment to support the colonists, biostocks to feed them, an unobtainium hull to contain this, an unobtainium fusion drive, and ice. Lots and lots of ice. We won't use the ice as a shield against the interstellar medium. We'll use it as fuel for our unobtainium space drive.
As far as protection against that interstellar medium, hey, we've got fusion. Just deploy a magical disruptor field in front of the spaceship that ionizes whatever of the medium isn't already ionized. A magnetic field will sweep the ionized medium around the spaceship. We don't need no stinking ice shield!
Suppose the colonists, the support environment and equipment, the biostocks, the unobtainium hull, the unobtainium propulsion system, etc. mass to 1000 metric tons. We need that unobtainium keep the mass this low. A thousand metric tons is a bit more than twice the mass of the International Space Station.
The spacecraft needs to start from a stop with respect to the Earth, coast for a while (a long while), and finally come to a stop with respect to the target planet at the target star. Why the coast? There isn't enough mass in the universe to have spaceship accelerate all the way to the halfway point, then turn around and decelerate to finally come to rest at the target. Why come to a stop? You don't want to have your colony ship drifting through space forever, do you?
Because you need to start from a rest, coast, and come to a stop you need to apply the rocket equation twice. Apply it once and you're already in trouble. Apply it twice and you are totally screwed. Let's play with some numbers. We have two variables at play, the exhaust velocity
ve and the coast velocity Δ
v. The rocket equation, applied twice, says that the mass of the ice needed for fuel in terms of the mass of the ship proper
mp (mass of the colonists+environment+biostocks+hull+drive) is
m_{\text{ice}} = m_p \left(e^{2\Delta v/v_e} - 1\right)
Suppose we want the coast velocity to be 1/10 the speed of light and the exhaust velocity is the best produced by a VASIMR-like drive, 120 km/s. This would require 3.7×10
219 metric tons of ice. That's 6×10
179 times the mass of the Milky Way. Obviously VASIMR does not have the woo-woo power needed. Upping the woo a bit, let's go with 500 km/s exhaust velocity, which is a fusion drive with exhaust speed augmented by a super duper ion thruster. (Those are NASA's words, not mine. See
http://www.nasa.gov/centers/glenn/technology/warp/ipspaper.html.) Now the mass of ice needed is only 2.2×10
27 times the mass of the Sun. Up the woo a bit more to an exhaust velocity of 1,000 km/s and you still need 6.7 Earth masses of ice.Up the woo even more (but now you are violating the laws of physics) to an exhaust velocity of 10,000 km/s and you still need 150,000 metric tons of ice.
Things become a bit more doable if the coast speed is 1/100 the speed of light, but now you have a multi-generation spaceship. That 150,000 metric tons of ice will now work with an exhaust velocity of 1,000 km/s. A 500 km/s exhaust velocity requires a lot more ice, 59 million metric tons of it.
The only escape is to not use a rocket. You can't carry the fuel with you.