How Much Money Did Frank Initially Have for School Supplies?

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Frank initially spent money on school supplies across three stores, ultimately returning home with $5. In the first store, he spent half of his initial amount plus $10. In the second store, he spent half of what remained plus another $10, and in the third store, he spent 80% of what was left. After working through the equations, it was determined that Frank started with $160. The discussion focused on correctly setting up the equations based on the amounts spent and remaining after each store visit.
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Homework Statement


Frank bought supplies for school. In the first store, he spent half his money plus $10. In the second store, he spent half of what he had left plus $10. In the third store, he spent 80% of what he had left. He came home with $5. How much did Frank start out with?

Homework Equations


The Attempt at a Solution


Any help would be appreciated.

Let x represent the original cost:
cYcdD.png
 
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I would say work in reverse start from the $5 and work your way back.
 
S.R said:

Homework Statement


Frank bought supplies for school. In the first store, he spent half his money plus $10. In the second store, he spent half of what he had left plus $10. In the third store, he spent 80% of what he had left. He came home with $5. How much did Frank start out with?


Homework Equations





The Attempt at a Solution


Any help would be appreciated.

Let x represent the original cost:
cYcdD.png

Obviously, x = -35 is not the right answer.

Write a single equation that has on one side the amounts he spent in the three stores + what he had left, and on the other side, the total amount he started with (x).
 
Mark44 said:
Obviously, x = -35 is not the right answer.

Write a single equation that has on one side the amounts he spent in the three stores + what he had left, and on the other side, the total amount he started with (x).

Or just do the inverse of what he spent starting out from $5.
 
The problem is your second equation... the problem reads, he spent half of what he had left and what you wrote would mean he spent half of what he spent in the first store. You made the same mistake when writing the last one, the problem reads 80% of what he had left and you wrote 80% of what he spent. Try rewriting those and work the solution again.
 
Mark44 said:
Obviously, x = -35 is not the right answer.

Write a single equation that has on one side the amounts he spent in the three stores + what he had left, and on the other side, the total amount he started with (x).

Thanks for the advice. I know -35 is incorrect, that's why I posted the problem.
 
Also, the assumption that S3 is equal to 5 is wrong, that's what was left, not wht he spent in the third store (which is what you should write in S3.
 
cesaruelas said:
Also, the assumption that S3 is equal to 5 is wrong, that's what was left, not wht he spent in the third store (which is what you should write in S3.

Is S2: [((x-(x/2+10))/2]-10?
 
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S.R said:
Is S2: [((x-(x/2+10))/2]-10?

I would only change the last element and make it a + 10, the rest is okay according to me.
 
  • #10
cesaruelas said:
I would only change the last element and make it a + 10, the rest is okay according to me.

By "plus $10" does this mean Frank spends an additional $10 or that he spends one half plus $10?
 
  • #11
S.R said:
In the first store, he spent half his money plus $10
If he starts off with x dollars, the above can be translated to x/2 + 10, the amount he spent in the first store.
 
  • #12
Mark44 said:
If he starts off with x dollars, the above can be translated to x/2 + 10, the amount he spent in the first store.

Yes. In the second store he spends (x-a)/2+10, where a=x/2+10. Correct? I'm still unclear on how to solve this problem.
 
  • #13
Looks good to me.

In store 1 he spent x/2 + 10, so he has left x - (x/2 + 10), or x/2 - 10.

In store 2 he spent half of what remained, plus $10.

Maybe it would help to make a table, listing how much he had when he went into each store, and how much when he came out.
 
  • #14
Mark44 said:
Looks good to me.

In store 1 he spent x/2 + 10, so he has left x - (x/2 + 10), or x/2 - 10.

In store 2 he spent half of what remained, plus $10.

Maybe it would help to make a table, listing how much he had when he went into each store, and how much when he came out.

Store 1: he spent x/2+10, so he has left x/2-10.

Store 2: he spent [(x/2-10)/2]+10 = x/4+5, so he has left (x/2-10)-(x/4+5) = x/4-15.

Store 3: he spent 4/5*[x/4-15] = x/5-12, so he has left (x/4-15)-(x/5-12) = x/20-3.

Is this correct?
 
  • #15
S.R said:
Store 1: he spent x/2+10, so he has left x/2-10.

Store 2: he spent [(x/2-10)/2]+10 = x/4+5, so he has left (x/2-10)-(x/4+5) = x/4-15.

Store 3: he spent 4/5*[x/4-15] = x/5-12, so he has left (x/4-15)-(x/5-12) = x/20-3.

Is this correct?

Continue doing what you're doing until you get an equation that you can solve for x. Once you have a value, check it.
 
  • #16
Mark44 said:
Continue doing what you're doing until you get an equation that you can solve for x. Once you have a value, check it.

Nevermind: answer is 160.
 
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