How much time does it take to lift the piano?

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To determine the time required to lift a 140 kg piano to an apartment 18 meters high using a crane with a power output of 400 W, the relevant equations for power and force are applied. The power equation P = Fv indicates that force can be calculated as F = P/v, leading to a force of approximately 22.22 N. Using the mass of the piano, the acceleration is found to be about 0.159 m/s². Finally, applying the equation v = at allows for the calculation of time, resulting in approximately 113.21 seconds to lift the piano. This solution effectively combines principles of physics to arrive at the final answer.
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Hello,

I thought I knew how to solve for this problem but alas I was wrong. I'm hoping someone will be able to point me in the right direction.

Here's the problem: A 1.40x10^2 kg piano is being lifted at a steady speed from ground level straight up to an apartment 18.0m above the ground. The crane that is doing the lifting produces a steady power of 4.00x10^2 W. How much time does it take to lift the piano?

So here's what I did:

The equation for power is P = W/t.

The equation for W (work done) is W = (Fcos0)s.

I have P (at least this is my thinking here). P is 4.00x10^2 and I would need to find W and then I could solve for t.

F = ma, however I don't know what my acceleration is. I calculated it with 9.80 but my answer was incorrect. So if all my original thinking in finding t is correct then all I really need help with is finding F.

Any help provided will be greatly appreciated.
 
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Stunner, that does not equal work.

Conservation of Mechanical Energy
\Delta K + \Delta \Omega = 0

By the way, if the speed is steady(i suppose it means constant) what will be the change of kinetic energy?

You could apply (Conservative System Work)

W = -\Delta \Omega

Alternatively,

Newton's 1st Law

\sum_{i=1}^{n} \vec{F}_{i} = 0 \rightarrow \vec{v} = constant

You could use this to establish the force exerted to lift it is equal to the weight of the piano, in magnitude.
 


Hi there,

To solve this problem, it would be helpful to use the equation P = Fv, where P is power, F is force, and v is velocity. In this case, we know that P = 4.00x10^2 W and v = 18.0 m/s (since the piano is being lifted at a steady speed of 18.0m above the ground). Therefore, we can rearrange the equation to solve for F: F = P/v. Plugging in the values, we get F = (4.00x10^2 W)/(18.0 m/s) = 22.22 N.

Now, we can use the equation F = ma to solve for the acceleration. We know that m = 1.40x10^2 kg, so we can rearrange the equation to solve for a: a = F/m. Plugging in the values, we get a = (22.22 N)/(1.40x10^2 kg) = 0.159 m/s^2.

Finally, we can use the equation v = at to solve for the time (t) it takes to lift the piano. We know that v = 18.0 m/s and a = 0.159 m/s^2, so we can rearrange the equation to solve for t: t = v/a. Plugging in the values, we get t = (18.0 m/s)/(0.159 m/s^2) = 113.21 seconds.

Therefore, it would take approximately 113.21 seconds (or 1 minute and 53 seconds) to lift the piano. I hope this helps and please let me know if you have any further questions.
 
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