How much water evaporates per minute from a copper pot on a stove?

AI Thread Summary
The discussion focuses on calculating the rate of water evaporation from a copper pot heated on a stove. The initial approach using the heat transfer equation is validated, but the second equation, Q=mcΔT, is deemed inappropriate since the water is already at its boiling point. Instead, the conversation emphasizes the need to apply the latent heat of vaporization equation, q=hfg, which accounts for the energy required for the phase change from liquid to gas. Participants clarify that during evaporation, all absorbed energy contributes to latent heat rather than increasing temperature. Ultimately, understanding the correct equations for phase transitions is crucial for accurate calculations.
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Homework Statement


a copper pot's radius is 12 cm, the thickness is 5 mm. It is placed on the stove for boiling, if the temperature of the stove is 115 oC while the water is 100 oC. How much of water that evaporates per minute

Homework Equations


ΔQ/Δt = (A)(k)(ΔT) / (L)
Q=mcΔT

The Attempt at a Solution



I 've calculated the rate of heat transferring in a minute with the first equation and I got the amount of the heat to calculate mass later with the second equation. Does my process correct?
 
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The method for calculating the heat per minute going in is correct. You need to rethink the second equation. The water is already at the boiling point so any heat that goes in it cannot raise its temperature. What does it do instead?
 
kuruman said:
The method for calculating the heat per minute going in is correct. You need to rethink the second equation. The water is already at the boiling point so any heat that goes in it cannot raise its temperature. What does it do instead?
it is changed into gas - steam? I know that when then heat reach the phase change, the temperature won't change anymore. How can I apply this with the second equation? Does the change in temperature still the same at 100oC because if there is no change in the temperature the whole equation will broke down (divided by 0)
 
You should not be looking at Q=mcΔT. What equation is applicable when you have a phase transition?
 
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In evaporation all energy absorbed is going to be latent and not sensible. Use this equation q=hfg [J/kg]. hfg represents the enthalpy of evaporation, this means, the specific energy required to go from one side of the dome(saturated liq) to the other side of the dome (saturated steam).
 
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