How much work is done lifting a leaking bucket from the bottom of a well?

In summary, the problem involves lifting a 12 lb bucket from the bottom of a 10 ft well to the top using a rope that weighs 0.6 lb/ft. The bucket initially contains 60 lb of water but the water leaks out at a constant rate, finishing draining at the top of the well. The work done is calculated using the equation w = \int_{a}^{b} [F(x)]dx and takes into account the weight of the bucket. The final answer is 330 lb-ft.
  • #1
Precursor
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Homework Statement


A leaky 12 lb bucket is lifted from the bottom of a 10 ft well to the top at
a constant speed with a rope that weighs 0.6 lb/ft. Initially the bucket contains 60 lb
of water but the water leaks at a constant rate and finishes draining just as the bucket
reaches the top of the well. How much work is done?


Homework Equations


[tex]w = \int_{a}^{b} [F(x)]dx[/tex]


The Attempt at a Solution


[tex]w = \int_{a}^{b} [F(x)]dx[/tex]

[tex]w = \int_{0}^{10} [0.6(10 - x) + 6(10 - x)]dx[/tex]

[tex]w = 330[/tex] lb-ft


Is this correct?
 
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  • #2
Don't forget the weight of the bucket. :wink:
 

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