How much work is done lifting a leaking bucket from the bottom of a well?

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SUMMARY

The problem involves calculating the work done in lifting a leaky bucket from the bottom of a 10 ft well. The bucket weighs 12 lb and initially contains 60 lb of water, which leaks out at a constant rate. The total work done is calculated using the integral w = ∫[F(x)]dx, resulting in a final answer of 330 lb-ft. The weight of the bucket and the rope, which weighs 0.6 lb/ft, are both factored into the calculation.

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Homework Statement


A leaky 12 lb bucket is lifted from the bottom of a 10 ft well to the top at
a constant speed with a rope that weighs 0.6 lb/ft. Initially the bucket contains 60 lb
of water but the water leaks at a constant rate and finishes draining just as the bucket
reaches the top of the well. How much work is done?


Homework Equations


w = \int_{a}^{b} [F(x)]dx


The Attempt at a Solution


w = \int_{a}^{b} [F(x)]dx

w = \int_{0}^{10} [0.6(10 - x) + 6(10 - x)]dx

w = 330 lb-ft


Is this correct?
 
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