they said that the solution of(adsbygoogle = window.adsbygoogle || []).push({});

[tex]-dn=-\frac{1}{\tau}ndt\\[/tex]

is

[tex]n=n_0e^{-\frac{t}{\tau}}[/tex]

i got a totaly different answer

[tex]-dn=-\frac{1}{\tau}ndt\\[/tex]

[tex]\int -dn=\int -\frac{1}{\tau}ndt\\[/tex]

[tex]\int \frac{-dn}{n}=\int -\frac{1}{\tau}dt\\[/tex]

[tex]-\ln{n}=-\frac{t}{\tau}\\[/tex]

[tex]\ln{n^{-1}}=-\frac{t}{\tau}\\[/tex]

[tex]e^{-\frac{t}{\tau}{={n^{-1}}[/tex]

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: How they say that it is the solution

**Physics Forums | Science Articles, Homework Help, Discussion**