How to Balance PhCHO + SF4 Reaction

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The reaction between PhCHO (benzaldehyde) and SF4 involves understanding the electron interactions and stability of the compounds. Benzaldehyde has two lone pairs on oxygen, two electrons in a pi bond, and resonance electrons in the benzene ring, which limits its reactivity. The positive charge on the carbonyl carbon is stabilized by the surrounding benzene ring and oxygen. The sulfur in SF4 will acquire a negative charge due to the addition of electrons, while the carbonyl carbon retains a positive charge. Consideration of these charges and the stability of sulfur is crucial for determining the reaction mechanism.
orgmann
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Please post this type of questions in HW section using the template.
There is reaction between
PhCHO + SF4
I tried to make the mechanism but I stuck .
1464172964490.jpg
 
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I'm not quite sure what PhCHO is, it seems as though it is benzaldehyde. If that's the case let's look at your electrons that can participate in bonding. You have two lone pairs on an oxygen, two electrons in a pi bond, and 6 pi electrons in resonance in your ring. These are the only electrons that will be able to form a bond and given the reactivity of benzene pi bonds, it's unlikely that they will be involved. Also think about you the stability. The positive carbon is fairly stable due to the benzene ring on one side and oxygen on the other.
 
Your last compound is wrong. The sulphur shall have a -ve charge due to accumulation of another pair of electrons and the carbonyl carbon shall have +ve charge. That should help you get the mechanism. Post that, think about the stability of the sulphur and how it can become more stable.
 

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