How to Calculate Acceleration in a Pulley System with Two Masses?

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SUMMARY

The discussion focuses on calculating the acceleration in a pulley system involving two masses, m1 = 2.9 kg and m2 = 5.3 kg, with a pulley that has a moment of inertia of 6.0 kgm² and a radius of 0.50 m. The correct approach involves using the equation r(T2 - T1) = (I)(a/r) to relate the tensions and angular acceleration. The final calculated acceleration is 1.6 m/s², but the initial attempts were incorrect due to misapplication of the formula. The participants emphasize the importance of correctly identifying the forces acting on the system.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with rotational dynamics and moment of inertia
  • Basic knowledge of pulley systems and tension forces
  • Ability to manipulate equations involving linear and angular acceleration
NEXT STEPS
  • Study the derivation of Newton's second law in rotational motion
  • Learn about the relationship between linear and angular acceleration in pulley systems
  • Explore examples of tension calculations in multi-mass pulley systems
  • Investigate the effects of friction and moment of inertia on system dynamics
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding dynamics in pulley systems will benefit from this discussion.

Touchme
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The pulley in Figure P8.59 has a moment of inertia of 6.0 kgm2 and a radius of 0.50 m. The cord supporting the masses m1 and m2 does not slip, and the axle is frictionless.

Find the acceleration of each mass when m1 = 2.9 kg and m2 = 5.3 kg.

Im not sure how to get started. What I did was r(T2 - T1) = (I)(a/r)
I got a = 1.6 but that is wrong
What am I doing wrong?

Nvm,, got the answer. thanks for lookin
 

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i have a question, how did u get the answer? I am really having trouble with that..if you don't mind? :) cuz' i tried a lot and i still don't have the answer...
 
xbabiemuahzx: Show us what you've tried so far and where you are stuck.
 

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