How to Calculate Area Enclosed by a Complex Polar Curve Using Green's Theorem?

  • Thread starter Thread starter Niskamies
  • Start date Start date
  • Tags Tags
    Area Curve
Click For Summary
SUMMARY

The discussion focuses on calculating the area enclosed by the polar curve defined by r = a*(cos t)^3 + b*(sin t)^3 for 0 < t < 2π using Green's Theorem. The area can be computed using the integral formula Integral[r(t)²/2 dt] with limits from 0 to 2π. It is crucial to accurately graph the function to determine the correct limits of integration. Additionally, the distinction between scalar and vector notation for r in polar coordinates is emphasized.

PREREQUISITES
  • Understanding of Green's Theorem in the Plane
  • Knowledge of polar coordinates and their applications
  • Familiarity with line integrals
  • Ability to graph polar functions
NEXT STEPS
  • Study the application of Green's Theorem for area calculations
  • Learn how to graph polar curves effectively
  • Explore the derivation of the area formula for polar coordinates
  • Practice solving line integrals in polar coordinates
USEFUL FOR

Students and educators in mathematics, particularly those studying calculus and vector analysis, as well as anyone interested in applying Green's Theorem to solve area problems involving polar curves.

Niskamies
Messages
1
Reaction score
0
The problem is the following:

Use a line integral to find the plane area enclosed by the curve r = a*(cos t)^3 + b*(sin t)^3, 0 < t <2*pi.

I don't really have a clue how to solve that. The chapter we are right now in is about Green's theorem in the Plane, and all the example problems use x and y instead of t.

I would be very glad i f somebody would tell how to solve this problem.
 
Physics news on Phys.org
I would integrate the curve 'r' wrt t, taking the limit to be 0 to 2pi.
 
This is easily done (I think) using polar coordinates.
If r(t) is the distance from the origin to the curve,
and if t is the polar angle around the origin,
then the surface is given by

Integral[r(t)²/2 dt,{t,tmin,tmax)]

You have to be careful to decide the limits of integration,
and therefore you need to make a correct graphic of this function to understand the shape you need to evaluate.
There may be some calucations to perform ...

Michel

Note:
On the lhs, you wrote r in bold.
Be careful, r is the distance in polar coordinates, it is not a vector and should not be written in bold.
 
Last edited:

Similar threads

Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K