How to calculate dA of a circle

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SUMMARY

The discussion focuses on calculating the differential area (dA) of a circle, specifically addressing the relationship between mass (m), radius (R), and area (A). The correct formula for dA is established as dA = r * dr * dθ, where r is the radius, dr is the small change in radius, and dθ is the small change in angle. The initial incorrect attempts at calculating dA highlight the importance of considering both radial and angular components in the calculation. The conversation clarifies that the context involves a disc rather than a simple circle.

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Homework Statement


Hello! I need to calculate a little fraction (dA) of the area of a circle (mass m and radius R and area A) and I have no idea how to do this.

Homework Equations


According to my textbook dm=\frac{M.dA}{A}=\sigma .dA and dA=R.dR.d\theta.

The Attempt at a Solution


Well, I tried to analyze the problem and my first thought was dA=\pi dR^2. This is obviously wrong so I tried to think a little bit more and this is what I got dA=R.dR... wrong again.
PS: is there a problem that I post here very often (create new topics)??

Thanks!
 
Last edited:
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This is a calculus question.

Why does your circle have mass? Do you mean a disc?

You almost had it with dA = r \; dr, but you need to account for the angle. Think of it like this: start at a point (r,\theta). From there, add a small radial distance dr and a small angle d\theta. Doing so should define a small rectangle. One side is just dr, but the other side, based on the change in angle, depends on how far away you are from the center of the circle: that side length is r \; d\theta.

The small differential area dA is then just the product of the two side lengths of the (nearly) rectangular shape we have: (dr)(r \; d\theta) = r \; dr \; d\theta.
 
Yes, sorry I was thinking about a disc. I think I got it now! Thank you for the answer and sorry for posting this question in the wrong forum.
 

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