How to calculate delivered luminosity?

  • Thread starter Thread starter Melumi
  • Start date Start date
  • Tags Tags
    Cms Luminosity
Melumi
Messages
2
Reaction score
0
I found CMS total delivered luminosity from Cern Statistics website (22.98 inverse fb). But i want to calculate myself and using values from website's supertable page. (https://acc-stats.web.cern.ch/acc-stats/#lhc/overview-panel)
But my result is 8.16E+42
Where is my mistake?
 
Physics news on Phys.org
On the third line of your calculations, the second plus sign should have been a minus sign. I'm sure that's it even though I have no idea what your calculations were. ;)
 
vela said:
On the third line of your calculations, the second plus sign should have been a minus sign. I'm sure that's it even though I have no idea what your calculations were. ;)

L= (n_b*f*N_1*N_2) / 4*pi*sigma_x*sigma_y*sqrt(1+(thetha*sigma_z/2*sigma_x)^2)
n_b: number of colliding pairs for CMS on supertable (01.01.2012 - 31.12.2012)
f: stable beam duration on supertable (01.01.2012 - 31.12.2012)

L= (my calculation on excel) = 1,58E+42
But i must found 23^fb-1 (01.01.2012 - 31.12.2012)

What is reduction factors for delivered luminosity?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top