How to Calculate Heat Loss in a Long Cable for a Single-Phase Load?

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SUMMARY

The discussion focuses on calculating heat loss in a long cable supplying a 69 kW single-phase load with a power factor of 0.68 lagging. The cable has an impedance of 0.011+j0.005 Ω per phase, and the voltage across the load is 230 V RMS. To determine the heat loss in watts, the magnitude of the current must first be calculated using the formula I = P / (V * PF), where P is the power, V is the voltage, and PF is the power factor.

PREREQUISITES
  • Understanding of single-phase power calculations
  • Knowledge of complex impedance in AC circuits
  • Familiarity with power factor concepts
  • Ability to apply Ohm's Law in electrical engineering
NEXT STEPS
  • Calculate the magnitude of the current using the formula I = P / (V * PF)
  • Learn about heat loss calculations in electrical cables
  • Explore the impact of power factor on energy efficiency
  • Study the effects of cable impedance on voltage drop and heat generation
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Electrical engineers, students studying power systems, and professionals involved in cable design and energy efficiency optimization.

Stivi
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Homework Statement


A 69 kW single-phase load with a power factor of 0.68 lagging is fed by a long cable with an impedance of 0.011+j0.005 Ω per phase. The voltage across the load is 230 V RMS. Calculate the heat loss in the cable in Watt [W].



Homework Equations





The Attempt at a Solution

 
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Stivi said:

The Attempt at a Solution


You might want to start by finding the magnitude of the current I.
 

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