Not one 100% sure (been a while since i practise physics) but would say if you know the volumn of water (or what ever liquid), the dimensions of the vortex + its volumn (cant remember the equation for finding the volumn of a cone) and the dimensions of the container you could come up with an equation, doubt it would be a direct case of the vortex volum being added to the top of the current liquids hieght in the container but you get the idea, sorry i couldn't be more help, its late and I've been up all day can't be coming up with calculations for you.