How to Calculate the Electric Field of Two Point Charges Along the x-Axis?

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SUMMARY

The discussion focuses on calculating the electric field vector E(x,0,0) due to two point charges (Q>0) located at coordinates (0,a,0) and (0,-a,0). The formula used is E = 1/(4πε₀) * Q/r², where r² = x² + a². Participants emphasized the importance of resolving the electric field components along the x and y axes to find the resultant vector. Clarification was provided on handling the direction of the electric field vectors, which have the same magnitude but opposite directions along the y-axis.

PREREQUISITES
  • Understanding of Coulomb's Law and electric field calculations
  • Familiarity with vector components and their addition
  • Knowledge of the coordinate system in three dimensions
  • Basic grasp of physics concepts related to point charges
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  • Study vector addition in electric fields
  • Learn about the concept of superposition in electrostatics
  • Explore the implications of charge placement on electric field strength
  • Investigate the effects of varying charge magnitudes on electric field calculations
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Students studying electromagnetism, physics educators, and anyone interested in mastering electric field calculations involving multiple point charges.

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Homework Statement


Here it goes.
2 pontual charges (Q>0), placed in (0,a,0) and (0,-a,0): calculate de vector E(x,0,0) along xx

Homework Equations


The Attempt at a Solution


I tried to use E=1/(4*pi*epsilon naught) * Q/r2
but when i make Q/(x ex + a ey)2 and (x ex + (-a) ey)2
i don't know what to do...
(I think i have doing something wrong)
:cry:
 
Last edited:
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but when i make Q/(x ex + a ey)2 and (x ex + (-a) ey)2
This step is not clear.
Here r^2 = x^2 + a^2.
Here E has the same magnitude but different direction. Take its components along X and y-axis and then take the resultant.
 
:smile:
thanks
 

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