amukher
- 2
- 0
The energy emitted by a body in watts/m2 is = εσT4. In the case of a perfect black body, ε=1. If the body only emits IR light, what should be the value of ε?
The discussion revolves around the calculation of energy emitted through infrared (IR) waves, focusing on the concept of emissivity (ε) in relation to different types of bodies, including perfect black bodies and real or grey bodies. Participants explore the implications of emissivity in thermal radiation and its dependence on material properties.
Participants express differing views on the applicability of emissivity for non-thermal light sources and the classification of bodies emitting only IR light. There is no consensus on the value of ε for such cases, and the discussion remains unresolved.
Participants highlight that emissivity can vary based on material properties and surface characteristics, and that there are complexities in defining and predicting these values.
If the "body" is a light source not due to thermal radiation, then there is no ε. A CO2 laser will not emit the same power as a remote control, even if they are at the same temperature.amukher said:If the body only emits IR light, what should be the value of ε?
The emissivity is material dependent and surface roughness dependent. For example polished metal and foil of the same metal will have different emissivities, as shown here.amukher said:The energy emitted by a body in watts/m2 is = εσT4. In the case of a perfect black body, ε=1. If the body only emits IR light, what should be the value of ε?
amukher said:If the body only emits IR light, what should be the value of ε?
DrClaude said:If the "body" is a light source not due to thermal radiation, then there is no ε. A CO2 laser will not emit the same power as a remote control, even if they are at the same temperature.
The emissivity depends on the body shape (e.g how smooth it is) and the material. There's no easy way to predict them, they are basically empirical valuesamukher said:Let us say that the atmosphere blocks all visible light wavelengths and allows only IR wavelengths to reach the earth. The Earth would then be a source of thermal radiation. To calculate the heat emitted by the earth, I would need the value of ε.