How to calculate the interference voltage?

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SUMMARY

The discussion focuses on calculating the interference voltage in a circuit involving a voltage divider. The user identifies the interference voltage as Ui, which is derived from the formula Ui = U2 * (j w .1) / (1000 + j w 0.1), where w is set to 2 * pi * 1e6 Hz. The circuit includes impedances of 1 kOhm and 100 mH, with the 100 mH in common with another circuit. The user seeks clarification on whether to consider R2 in their calculations.

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Homework Statement
"The strip conductor LB that is common to both circuits has an inductance of 100mH. The resistance of the common trace portion is negligibly small. The amplitude of u2 is 10V and f=1MHz. Due to the galvanic coupling via the trace component LB, there is an interference voltage at the measuring amplifier. Determine the interference voltage."
Relevant Equations
voltage divider
Hello everyone,

I have this circuit and I need to determine the interference voltage.
1676732809984.png

I am not sure, where the interference voltage is applied and how to determine it. I think the interference voltage is uv nad my equivalent circuit looks like this:

1676732925957.png

Am I in heading into the right direction? Do I need to consider R2 as well? I would be very thankful if you help me solving this.
 
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This is a voltage divider problem. The impedances for the U2 circuit are 1 kOhm + 100 mHenry. The 100 mH is in common with the U1 circuit. Hence, the interference voltage Ui = U2 * (j w .1) / (1000 + j w 0.1). w in this case is 2 * pi * 1e6 Hz. Note the Ui you will get from this is a complex value, from which you will want to compute its magnitude.
 

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