How to Calculate the Internal Resistance of a Battery?

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SUMMARY

The discussion focuses on calculating the internal resistance of a battery using a torch bulb rated at 2.5V and 0.3A connected to a dry battery with an electromotive force (e.m.f) of 3.0V. The voltage drop across the bulb is confirmed to be 2.5V, leading to the conclusion that the internal resistance of the battery is 1.67 ohms. Participants emphasize the importance of showing work in calculations to facilitate understanding.

PREREQUISITES
  • Understanding of Ohm's Law (I=V/R)
  • Familiarity with electromotive force (e.m.f) concepts
  • Basic knowledge of electrical circuits
  • Ability to perform calculations involving resistance and voltage
NEXT STEPS
  • Study the principles of internal resistance in batteries
  • Learn how to apply Ohm's Law in practical scenarios
  • Research methods for measuring battery e.m.f and internal resistance
  • Explore circuit analysis techniques for voltage and current calculations
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone interested in understanding battery performance and circuit behavior.

SJN
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Homework Statement


A torch bulb is marked 2.5V and 0.3A. When it is connected to a dry battery of e.m.f 3.0V the correct p.d of 2.5V is produced across it. Calculate the internal resistance if the battery.

Homework Equations


I=V/R?

The Attempt at a Solution


It's on paper - sorry!Answer = 1.67 - But how you get to that is the question - working out must be shown.

Thanks in advance,
Sam
 
Last edited:
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SJN said:
Answer = 1.67 - But how you get to that is the question - working out must be shown.
We do not provide solutions here. We will help you will your homework, but you have to show some effort first, by typing out your attempted solution for example.

The same goes for your other thread, "I don't know how to start" isn't an attempted solution.
 
OK Sorry,

It's just I tried to find my tutor today, and couldn't see him, so I'm a little puzzled.

Not to worry, have a good day.
 

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