How to Calculate the X-Component of the Magnetic Moment in a Rectangular Loop?

AI Thread Summary
To calculate the x-component of the magnetic moment (μx) for a rectangular loop of wire in a magnetic field, first determine the area (A) using the formula A = H * W, where H is the height and W is the width of the loop. The magnetic moment is then calculated as μ = A * I, with I being the current flowing through the loop. The angle θ, which is 30° in this case, affects the orientation of the magnetic moment vector, and it is crucial to accurately represent this angle in your calculations. The confusion arises in determining the correct angle for μx, which requires careful consideration of the loop's orientation relative to the x-axis. Properly drawing the magnetic moment vector and noting its angle is essential for an accurate solution.
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Homework Statement


A rectangular loop of wire with sides H = 22 cm and W = 77 cm is located in a region containing a constant magnetic field B = 0.82 T that is aligned with the positive y-axis as shown. The loop carries current I = 334 mA. The plane of the loop is inclined at an angle θ = 30° with respect to the x-axis.
h13_rectangle.png

What is μx, the x-component of the magnetic moment vector of the loop?

Homework Equations


μ = AI
A = H*W

The Attempt at a Solution


I attempted to solve the question by solving for μ like μx = H*W*cos(30°) however this is not the correct answer. Thanks in advance!
 
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Be sure you draw the magnetic moment vector on your diagram and carefully note the angle that the vector makes to the x-axis or the y-axis.
 
TSny said:
Be sure you draw the magnetic moment vector on your diagram and carefully note the angle that the vector makes to the x-axis or the y-axis.
I'm a little confused on how to find the angle that the vector maxis to the x-axis.
 
What is the rule for determining the direction of the magnetic moment vector?
 

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