How to Calculate Travel Time for a Maglev Train in a Vacuum?

Click For Summary

Discussion Overview

The discussion revolves around calculating the travel time for a maglev train operating in a vacuum, focusing on the effects of acceleration and deceleration on travel time as a function of distance. The scope includes theoretical considerations of physics and engineering related to high-speed travel.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant proposes that the travel time can be calculated using the formula t = √(4s/g), where t is time, s is distance, and g is acceleration.
  • Another participant questions what value of acceleration (g) should be used to ensure passenger comfort, suggesting that a lower acceleration would be preferable.
  • A different participant suggests an acceleration of 0.5 m/s², claiming that this would allow a maglev train to traverse the USA in 1.5 hours, with a proposed top speed of 2.7 km/s.
  • One participant reiterates the initial premise about acceleration and deceleration, providing an alternative expression for time as t = √(x/g) based on the distance traveled during acceleration.

Areas of Agreement / Disagreement

Participants express varying opinions on the appropriate acceleration value for comfort, and there is no consensus on the specific calculations or assumptions regarding travel time. Multiple competing views remain regarding the parameters involved in the calculations.

Contextual Notes

Participants have not settled on the definitions of acceleration values or the implications of passenger comfort on travel time calculations. The discussion includes assumptions about straight-line travel and does not address intermediate stops or other practical considerations.

yrh
Messages
2
Reaction score
0
Say we have a maglev train traveling i a vacuum. The only thing limiting its speed is the g-force tolerance of the passengers.

The train would therefore accelerate at a certain rate until halfway, and then decelerate until it reached its destination.

What would be the traveling time of such a train as a function of the distance?
 
Physics news on Phys.org
[tex]t=\sqrt{\frac{4s}{g}}[/tex]
where t is the time, s is the distance and g is the accelleration.
Calculated using the fact that distance traveled is the area underneath a velocity-time graph.
 
Thank you.

What acceleration value g should I use? I'm looking for an acceleration/deceleration that is hardly noticeable for the passengers, making the journey comfortable.
 
With an acceleration of 0.5m/s^2 you can cross the USA in 1.5h in a straight line, which is pretty good...

The chairs could turn 180 degrees when the train is going to decelerate. The top speed would be 2.7km/s.

The usual problem with trains is that they start and stop at all the intermediate stations...
 
yrh said:
Say we have a maglev train traveling i a vacuum. The only thing limiting its speed is the g-force tolerance of the passengers.

The train would therefore accelerate at a certain rate until halfway, and then decelerate until it reached its destination.

What would be the traveling time of such a train as a function of the distance?

At the distance x the train is accelerated until x/2 so the time is expressed as:
x/2=gt²/2
t=√x/g
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
7
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 26 ·
Replies
26
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 46 ·
2
Replies
46
Views
12K
  • · Replies 5 ·
Replies
5
Views
9K