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Using the Mayer–Vietoris sequence, how can we calculate the
De Rham cohomology of the Kelin bottle?
De Rham cohomology of the Kelin bottle?
The discussion focuses on computing the De Rham cohomology of the Klein bottle using the Mayer–Vietoris sequence. Participants confirm that the Klein bottle has the same cohomology as the torus, achieved by covering it with two Möbius strips. The cohomology of these strips, along with their intersection, is established as equivalent to that of the circle. The conclusion is that the Klein bottle and the torus share the same cohomological properties.
PREREQUISITESMathematicians, topologists, and students interested in algebraic topology and cohomological theories, particularly those studying the properties of surfaces like the Klein bottle and torus.
morphism said:First step would be to find a good open cover. Have you done so yet?
zhentil said:I don't think those are cylinders ;)
Once you figure out what they are (and compute their cohomology, which is pretty straightforward), you'll have the answer.
zhentil said:Why do they have the same cohomology as the cylinder? That's certainly not true.
morphism said:That's the open cover I had in mind. Those two mobius strips and their intersection (another mobius strip) have the cohomology of the circle. In fact, it turns out that the Klein bottle does as well.
So either you haven't computed the cohomology of the torus correctly, or you're messing up the MV argument.