How to Determine the Decay Constant of a Radioactive Substance?

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Homework Help Overview

The discussion revolves around determining the decay constant of a radioactive substance based on its count rate and the number of atoms present. The context involves concepts from nuclear physics and radioactive decay.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore assumptions regarding count rates, initial atom quantities, and detector efficiency. There are attempts to apply the radioactive decay equation, with some questioning the impact of the detector's efficiency on the calculations.

Discussion Status

The discussion has progressed with participants providing calculations and insights. Some guidance has been offered regarding the importance of detector efficiency, leading to a clearer understanding for one participant. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants note the need to consider the efficiency of the detector, which is stated to be 5%, and how this affects the calculations. There is also mention of language barriers impacting understanding.

sweminka
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A piece of radioactive substance gives a received count rate of 6000 counts per minute in a detector whose efficiency is known to be 5%. If the sample contains 10^10 atoms, what is the decay constant ( λ ) of this radioactive substance ?

No idea how to solve this problem. Any help would be really appreciated.

Edit: I am a medical student studying abroad, and the physics teacher doesn't speak English properly. Please believe that I have tried to understand, but after 1 day of looking for information on the internet, I still have no idea how to solve this problem.
 
Last edited:
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Hi there,

To answer your question, there are many assumptions to be made:
1. I assume 6000 counts/minute in the first minute.
2. 10^{10} atoms is supposed to be be the initial excited/radioactive atoms in the sample
3. 6000 counts/minute assumes that all radiation emitted passes through the detector, with a 5% efficiency.

If all these assumptions are true, then you can simply apply the radioactive decay equation to your problem and the answer is solved in two lines.
 
Here are my calculations :

N(t)=No*exp(-λt)

10^10 - 6000 = (10^10) * exp (-λ*60)

( 10^10 -6000) / (10^10) = exp (-λ*60)

ln ( ( 10^10 -6000) / (10^10) ) = -λ*60

λ= ( - ln ( ( 10^10 -6000) / (10^10) ) ) / 60

λ = 10*(-8) per second
 
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The answer is supposed to be 2*10^(-7) though :(

I guess it has something to do with the detector's efficiency ?
 
Last edited:
Hi there,

You are forgetting the efficiency of the detector in your calculations. Don't forget that only 5% of the particles are detected.
 
"only 5% of the particles are detected" This sentence suddenly made everything clear to me. I guess I couldn't understand the meaning of "efficiency". Anyway, I replaced 6000 by 120 000 (100%) in my calculations, and I find the correct answer.

Thank you very much :)
 

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